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CBSE Class 10 Answered

Find three consecutive terms in A.P whose sum is 9 and the product of their cubes is 3375 
Asked by pushpa.Kudle09 | 12 Mar, 2020, 12:37: AM
Expert Answer
Let the consecutive terms of an A.P. be a - d, a, a + d 
a - d + a + a + d = 9
3a = 9
a = 3
 
Also
(a - d)3 + a3 + (a + d)3 = 3375
Solving this we get the value of d and then terms after putting a = 3
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