solve this cbse problem

Asked by  | 19th Jul, 2008, 10:56: PM

Expert Answer:

A=81

suppose the no of protons=p

so, no of neutrons = p + (p x 31.7/100)

                                  =1.317p

p+n=81

p+1.317p=81

p= 81/2.317=34.96=35

Answered by  | 20th Jul, 2008, 03:42: PM

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