solve this cbse problem
Asked by | 19th Jul, 2008, 10:56: PM
Expert Answer:
A=81
suppose the no of protons=p
so, no of neutrons = p + (p x 31.7/100)
=1.317p
p+n=81
p+1.317p=81
p= 81/2.317=34.96=35
Answered by | 20th Jul, 2008, 03:42: PM
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