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CBSE Class 10 Answered

Solve The Following Simultaneous Equation 5p+7q=26;2p+3q=11
Asked by amoghmohite | 27 Aug, 2021, 07:49: PM
answered-by-expert Expert Answer
5 p + 7 q = 26 .......................... (1)
 
2 p + 3 q = 11 ...........................(2)
 
 
multiply eqn.(1) by 2 ,  10 p + 14 q = 52 ......................(3)
 
multiply eqn.(2) by 5 ,  10 p + 15 q = 55 ......................(4)
 
By subtracting eqn.(3 ) from eqn.(4) , we get q = 3 
 
If we substitute q = 3 in eqn.(1) , we get , 5 p + 7(3) = 26  or  5 p = 5 or  p =1 
 
Hence we get , p =1 and q = 3
Answered by Thiyagarajan K | 17 Sep, 2021, 02:21: PM

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