Request a call back

Solve The Following Simultaneous Equation 5p+7q=26;2p+3q=11
Asked by amoghmohite | 27 Aug, 2021, 07:49: PM
5 p + 7 q = 26 .......................... (1)

2 p + 3 q = 11 ...........................(2)

multiply eqn.(1) by 2 ,  10 p + 14 q = 52 ......................(3)

multiply eqn.(2) by 5 ,  10 p + 15 q = 55 ......................(4)

By subtracting eqn.(3 ) from eqn.(4) , we get q = 3

If we substitute q = 3 in eqn.(1) , we get , 5 p + 7(3) = 26  or  5 p = 5 or  p =1

Hence we get , p =1 and q = 3
Answered by Thiyagarajan K | 17 Sep, 2021, 02:21: PM

## Concept Videos

CBSE 10 - Maths
Asked by Karamsingh5280 | 30 Sep, 2021, 01:07: PM
CBSE 10 - Maths
Asked by amoghmohite | 27 Aug, 2021, 07:49: PM
CBSE 10 - Maths
Asked by snehaljain870 | 07 Sep, 2019, 06:58: PM
CBSE 10 - Maths
Asked by chanderaop19527 | 25 Jun, 2019, 08:07: PM
CBSE 10 - Maths
Asked by Topperlearning User | 08 Aug, 2017, 11:31: AM
CBSE 10 - Maths
Asked by Topperlearning User | 08 Aug, 2017, 11:07: AM