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CBSE Class 10 Answered

solve the following pair of equations. begin mathsize 12px style square root of 3 space straight x space plus space square root of 2 space end root space straight y equals 2 square root of 3 space plus space square root of 2 space comma
straight x equals 1 plus straight y rightwards double arrow straight x minus straight y equals 1 end style
Asked by Topperlearning User | 08 Aug, 2017, 11:00: AM
answered-by-expert Expert Answer

begin mathsize 12px style The space given space system space of space equations space
square root of 3 space straight x space plus space square root of 2 space end root space straight y equals 2 square root of 3 space plus space square root of 2 space comma
straight x minus straight y equals 1
By space cross space multiplication space we space have
fraction numerator straight x over denominator square root of 2 plus 2 square root of 3 plus square root of 2 end fraction equals fraction numerator straight y over denominator 2 square root of 3 plus square root of 2 minus square root of 3 end fraction equals fraction numerator 1 over denominator square root of 3 plus square root of 2 end fraction
straight x equals fraction numerator 2 open parentheses square root of 3 plus square root of 2 close parentheses over denominator square root of 3 plus square root of 2 end fraction equals 2 comma space space space space space straight y equals fraction numerator square root of 3 plus square root of 2 over denominator square root of 3 plus square root of 2 end fraction equals 1 end style

         

         

         

Answered by | 08 Aug, 2017, 01:00: PM

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