solve the following pair of equations.

begin mathsize 12px style square root of 3 space straight x space plus space square root of 2 space end root space straight y equals 2 square root of 3 space plus space square root of 2 space comma
straight x equals 1 plus straight y rightwards double arrow straight x minus straight y equals 1 end style

Asked by Topperlearning User | 8th Aug, 2017, 11:00: AM

Expert Answer:

begin mathsize 12px style The space given space system space of space equations space
square root of 3 space straight x space plus space square root of 2 space end root space straight y equals 2 square root of 3 space plus space square root of 2 space comma
straight x minus straight y equals 1
By space cross space multiplication space we space have
fraction numerator straight x over denominator square root of 2 plus 2 square root of 3 plus square root of 2 end fraction equals fraction numerator straight y over denominator 2 square root of 3 plus square root of 2 minus square root of 3 end fraction equals fraction numerator 1 over denominator square root of 3 plus square root of 2 end fraction
straight x equals fraction numerator 2 open parentheses square root of 3 plus square root of 2 close parentheses over denominator square root of 3 plus square root of 2 end fraction equals 2 comma space space space space space straight y equals fraction numerator square root of 3 plus square root of 2 over denominator square root of 3 plus square root of 2 end fraction equals 1 end style

         

         

         

Answered by  | 8th Aug, 2017, 01:00: PM