CBSE Class 11-science Answered
Solve the 2nd part of 9th ques written in pencil
Asked by lovemaan5500 | 08 Oct, 2018, 05:14: PM
Expert Answer
The following answer is for 2nd part of 6th question as per written.
x2 + y2 - 5x + 2y - 5 = 0
Let the origin be shifted to (X, Y)
Hence,
x = X + h and y = Y + k
Put it in the given equation we get
(X + h)2 + (Y + k)2 - 5(X + h) + 2(Y + k) - 5 = 0
X2 + 2Xh + h2 + Y2 + 2Yk + k2 - 5X - 5h + 2Y + 2k - 5 = 0
X2 + h2 + Y2 + 2Xh - 5X + 2Yk + 2Y + k2 - 5h + 2k - 5 = 0
X2 + h2 + Y2 + (2h - 5)X + (2k + 2)Y + k2 - 5h + 2k - 5 = 0
According to the question.
2h - 5 = 0 and 2k + 2 = 0
h = 5/2 and k = -1
Answered by Sneha shidid | 10 Oct, 2018, 12:05: PM
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