Asked by | 9th Mar, 2010, 10:33: PM
B is present on corners and face centres with number of B atoms on face centres along one of the axis are removed.
A is present on body centre and edge centres.
Number of B atoms = 8 x (1/8) + 4 x (1/2) = 3
Number of A atoms = 12 x (1/4) + 1 = 4
Formula of the compound = A4B3
Answer is C
Answered by | 10th Mar, 2010, 04:23: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number