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Sir solve question number 22
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Asked by brijk456 | 24 Jul, 2019, 09:27: AM
answered-by-expert Expert Answer
We know, 
 
R space equals space square root of P squared space plus space Q squared space plus space 2 P Q cos theta end root space .... (*)
Initially consider two forces, √3 N and √3 N. The angle between the two forces is 60° 
we get, 
R equals space square root of 3 space plus space 3 space plus space 2 cross times square root of 3 cross times square root of 3 cross times cos space 60 degree end root space therefore space R space equals space square root of 3 space plus space 3 space plus space 2 space cross times 3 cross times 1 half end root space equals space 3 space N space  
Now, consider two vectors 2 N and 2 N. The angle between these two vectors is 120° 
 
Thus, substituting the value in (*) we get, 
 
R space equals space square root of 4 space plus 4 plus space 2 space cross times space 4 cross times space cos space 120 degree end root space R space equals space space square root of 4 space plus 4 space plus space 2 space cross times space 4 cross times space fraction numerator negative 1 over denominator 2 end fraction end root space equals space 2 space N space  
 
 
Thus, the resultant force acting on the particle P is, 
= 5 N + 2N + 3 N 
= 10 N 
 
Correct option is (1) - 10 N making angle of 60° with X - axis. 
Answered by Shiwani Sawant | 24 Jul, 2019, 12:03: PM
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