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Asked by Surjitsp6u | 05 Aug, 2019, 14:36: PM
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Let S be the sum of first n terms of a G.P.
R be the sum of the reciprocals of the first n terms of a G.P.
P be the product of the first n terms of a G.P.
We have the result P2Rn=Sn .... (i)
S = sum of first 24 terms of a G.P. = 2
P = Product first 24 terms of a G.P. = 2n
R = Sum of reciprocal of first 24 terms = 1
Using (i), we have
open parentheses 2 to the power of n close parentheses squared open parentheses 1 close parentheses to the power of 24 equals 2 to the power of 24 rightwards double arrow 2 n equals 24 rightwards double arrow n equals 12
Answered by Renu Varma | 06 Aug, 2019, 10:32: AM
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