JEE Class main Answered
Sir pls solve the following.
Asked by rsudipto | 02 Jan, 2019, 19:42: PM
Expert Answer
As from newton law of cooking (T1-T2)/time= k((T1+T2)/2 -Tsu)
Now put the value of temperature and time for first case
(75-70)/t1 =k ((75+70)/2 -Tsu)
For 2nd case
(70-65)/t2= k((70+65)/2- Tsu)
For 3rd case
(65-60)/t3=k((65+60)/2 -Tsu)
If u divide all the equation you can get idea
t1<t2<t3.
Answered by Ankit K | 03 Jan, 2019, 11:34: AM
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