Sir please provide solution

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Sir please provide solution

Asked by sanjaysingh.srct | 23 Aug, 2019, 12:47: PM

Expert Answer

3^{2x - 3} - 9^{x - 1} + 27^2x/3 = 675

3^2x/3³ - 9^x/9 + 3^3×2^x/3= 675

3^2x/3³ - 3^2x/9 + 3²^x= 675

Let 3^2x = m

m/27 - m/9 + m = 675

solving we get 3^x = 27 = 3³

x = 3

Answered by Sneha shidid | 23 Aug, 2019, 13:01: PM

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