Sir\Madam please explain me this question on Arithmetic Progressions!!
Asked by | 11th Jan, 2010, 02:42: PM
Let the four parts be a-3d, a-d, a+d and a+3d.
a-3d + a-d + a+d + a+3d = 20
a = 5.
(a-3d)(a+3d)/((a-d)(a+d)) = 2/3
(a2-9d2)/(a2-d2) = 2/3
(25-9d2)/(25-d2) = 2/3
25 - 9d2= 50/3 - 2d2/3
This gives d = ±1,
Hence the four parts are,
2, 4, 6, 8
Answered by | 11th Jan, 2010, 03:09: PM
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