Sir\Madam please explain me these questions on Arithmetic Progressions!!
Asked by
| 10th Jan, 2010,
11:08: PM
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Answer of question 1:
Let the two numbers be x and y.
Sum of two numbers = x + y = 13/6
Let n number of terms are inserted between x and y.
Then the total number of terms of the Ap become (n+2).
According to the given condition,
Sum of the terms of the new AP = (n + 2) + 1
⇒ (n+2)/2 {first term + last term} = (n+ 3)
⇒ ((n+2)/2) (x+y) = (n+3)
⇒ ((n+2)/2) (13/6) = (n+3)
⇒ 13n + 26 = 12n + 36
⇒ n = 10
So, 10 numbers are inserted between the given two numbers x and y.
Answered by
| 11th Jan, 2010,
09:35: AM
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