Sir\Madam please explain me these questions on Arithmetic Progressions!!

Asked by  | 10th Jan, 2010, 11:08: PM

Expert Answer:

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Answer of question 1:

Let the two numbers be x and y.

Sum of two numbers = x + y = 13/6

Let n number of terms are inserted between x and y.

Then the total number of terms of the Ap become (n+2).

According to the given condition,

Sum of the terms of the new AP = (n + 2) + 1

⇒ (n+2)/2 {first term + last term} = (n+ 3)

⇒ ((n+2)/2) (x+y) = (n+3)

⇒ ((n+2)/2) (13/6) = (n+3)

⇒ 13n + 26 = 12n + 36

⇒ n = 10

So, 10 numbers are inserted between the given two numbers x and y.


Answered by  | 11th Jan, 2010, 09:35: AM

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