JEE Class main Answered
sin 78 degree-sin66degre-sin 42degree+sin6degree
Asked by amitras0003 | 26 Jan, 2024, 06:53: AM
let x = sin78° - sin42° - sin66° + sin6°
= sin(60+18)° - sin(60-18)° - sin(36+30)+sin(36-30)
Let us use the trignometry identity " sin(A+B) - sin(A-B) = 2 cosA sinB "
= 2 cos60° sin18° - 2 cos36° sin30°
= sin18° - cos36°
=sin18° - (1 - 2 sin218) = 2 sin218 + sin18° - 1 = -0.5
Answered by Thiyagarajan K | 26 Jan, 2024, 17:06: PM
JEE main - Maths
Asked by yadavankith998 | 25 Jul, 2024, 22:08: PM
JEE main - Maths
Asked by swapnanemuturi | 24 Jul, 2024, 20:17: PM
JEE main - Maths
Asked by kumaraaditya2008 | 24 Jun, 2024, 17:19: PM
JEE main - Maths
Asked by sagnikguha2008 | 20 Jun, 2024, 10:28: AM
JEE main - Maths
Asked by abhayakumarsahoo3654 | 15 Jun, 2024, 18:26: PM
JEE main - Maths
Asked by gargkumar.9999 | 02 Jun, 2024, 12:06: PM
JEE main - Maths
Asked by pandu.munganda | 10 May, 2024, 11:00: AM
JEE main - Maths
Asked by keerthananukala2007 | 02 May, 2024, 11:32: AM