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# CBSE Class 11-science Answered

S=ut+(1/2)at^2

Asked by geetasinghaastha | 16 Aug, 2021, 08:07: PM
Distance S travelled by a body that is moving with uniform acceleration is given as

Distance S = Average velocity × time

Let u is initial velocity , v is final velocity after time t .

Average velocity = ( u + v) /2

Final velocity v is given as , v = u + ( a × t )

where a is uniform acceleration

Hence average velocity = [ u + u + ( a × t ) ] /2  = u + [ (1/2) a × t ]

Distance S travelled int time t ,  S = { u + [ (1/2) a × t ] } × t =  ( u t ) + [ (1/2) a t2 ]
Answered by Thiyagarajan K | 16 Aug, 2021, 08:28: PM

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