Respected sir/mam
please solve the following question...
 
(secA - tanA)blank squared  (1+sinA) = 1-sinA 

Asked by dazzlerumix | 19th Jul, 2014, 10:14: PM

Expert Answer:

C o n s i d e r space t h e space l e f t space h a n d space s i d e space o f space t h e space g i v e n space e q u a t i o n : L. H. S equals open parentheses s e c A minus tan A close parentheses squared open parentheses 1 plus sin A close parentheses equals open parentheses s e c A minus tan A close parentheses squared open parentheses 1 plus sin A close parentheses fraction numerator open parentheses 1 minus sin A close parentheses over denominator open parentheses 1 minus sin A close parentheses end fraction equals fraction numerator open parentheses s e c A minus tan A close parentheses squared open parentheses 1 minus sin squared A close parentheses over denominator open parentheses 1 minus sin A close parentheses end fraction equals fraction numerator open parentheses s e c A minus tan A close parentheses squared open parentheses cos squared A close parentheses over denominator open parentheses 1 minus sin A close parentheses end fraction equals fraction numerator open parentheses s e c A cross times cos A minus tan A cross times cos A close parentheses squared over denominator open parentheses 1 minus sin A close parentheses end fraction equals fraction numerator open parentheses 1 minus sin A close parentheses squared over denominator open parentheses 1 minus sin A close parentheses end fraction equals 1 minus sin A equals R. H. S H e n c e space p r o v e d.

Answered by Vimala Ramamurthy | 20th Jul, 2014, 07:43: AM