Related to integers and rational numbers. Please solve in detail.
Asked by Ambujsahu | 21st Jun, 2010, 02:46: PM
the given expression is
(16n2 + 7n + 6)/n
This can also be expressed as
=> (16n2/n) + (7n/n) + (6/n)
=> 16n + 7 + (6/n)
Now, since n is an integer, 16n and 7 , and hence 16n + 7 will be integer for all integral values of n. However, (6/n) will be an integer for only four values of n , n = 1,-1,6 and -6. For all other values of n, (6/n) will be fractional number.
Hence, the given expression will have integral values for only 4 integral values (1,-1,6,-6) of n.
Answered by | 15th Jul, 2010, 02:31: PM
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