Question on Empirical Formula.
Asked by RACHIT_MAHAAN
| 18th Jul, 2010,
05:12: PM
Expert Answer:
Divide the percentage by atomic mass of each:
Al =10.5/27 = 0.39
K =15.1/39= 0.39
S =24.96/32 = 0.78
O = 49.92/16 = 3.12
The simple ratios are = Al:K:S:O = 1 : 1 : 2 : 8
Ans: Empirical formula = KAlS2O8
Molar mass of anhydrorus salt = 258.21
This was 54.4% of the mass of the hydrated compound
Therefore the hydrated compond has a mass of 258.21/0.544 = 474.65
The mass due to water would be 474.65 - 258.21 = 216.44
This is equal to 12 moles of water.
The compound is KAl(SO4)2.12H2O
The simple ratios are = Al:K:S:O = 1 : 1 : 2 : 8
Ans: Empirical formula = KAlS2O8
Molar mass of anhydrorus salt = 258.21
This was 54.4% of the mass of the hydrated compound
Therefore the hydrated compond has a mass of 258.21/0.544 = 474.65
The mass due to water would be 474.65 - 258.21 = 216.44
This is equal to 12 moles of water.
The compound is KAl(SO4)2.12H2O
Answered by
| 21st Jul, 2010,
01:49: PM
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