CBSE Class 10 Answered
ques
Asked by nishac | 28 Feb, 2010, 09:59: AM
Expert Answer
Area of a triangle with vertices, (x1, y1),(x2, y2) and (x3, y3) is given by,
A = (1/2)(T)
where, T is the determinant,
| x1 y1 1 |
T = | x2 y2 1 |
| x3 y3 1 |
Using these,
Area = (1/2)((p-3)+(-2)(2-p)+(3+p)(3-2))
5 = (1/2)((p-3)+(-2)(2-p)+(3+p)(3-2))
10 =(p-3)+(-4+2p)+(3+p)
10 =4p-4
p = 14/4 = 7/2
The coordinates of third vertex are, (7/2, 13/2)
regards,
Team,
TopperLearning.
Answered by | 28 Feb, 2010, 11:46: AM
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