Q.

Asked by Int123 | 31st May, 2016, 09:41: PM

Expert Answer:

2C2H6 +7O2 →   4CO2 +6H2O

2 V       7 V        4 V

 

Now from equation, 2V of ethane reacts with = 7 V of oxygen

So, 600cc of ethane reacts with= 600 X 7/2 = 2100cc

 

Hence, unused O2 is = 2500 - 2100 = 400 cc

 

From 2V of ethane = 4 V of CO2 is produced

So, 600cc of ethane will produce = 4 X 600/2 =1200cc CO2

Answered by Vaibhav Chavan | 1st Jun, 2016, 10:38: AM