CBSE Class 12-science Answered
Q) The following data.......
Asked by | 11 Oct, 2009, 09:30: PM
Expert Answer
2.303
K =----------------------- log p0/ 2po - pt
2.303
K =----------------------- log 0.5/ 20.5 - 0.6
100
=2.2318 X 10-3s-1
now p0 +x = 6.5
x= 0.15
pso2cl2 = p0 - x
=.35
required rate = 2.2318 x 10-3 x 0.35
= 7.18 x 10-4 atms-1
t
Answered by | 12 Oct, 2009, 09:55: AM
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