Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

Q. An electric Lamp is rated 220 V and 50 W. Find the power consumed when it is operated on 120 V.
Asked by Trisha Gupta | 10 Jun, 2021, 06:46: PM
answered-by-expert Expert Answer
Let us find out the resistance R of the bulb that has power rating 50W when it is operating in 220 V .
 
Power P = V2 / R  
 
where V is voltage and R is resitance 
 
Hence resistance R = V2 / P = ( 220 × 220 ) / 50 = 968 Ω
 
When this bulb is connected to 120 V , then  consumed power P is given as
 
P = ( 120 × 120 ) / 968 =  14.876 W
 

Answered by Thiyagarajan K | 10 Jun, 2021, 07:24: PM
CBSE 10 - Physics
Asked by agankitgupta938 | 18 Apr, 2024, 04:29: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by infinityupgraded | 13 Apr, 2024, 08:17: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by suryamr2019 | 08 Mar, 2024, 04:32: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by shrilakshmimunoli | 01 Mar, 2024, 01:15: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by khajannirwan | 27 Feb, 2024, 10:20: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by sailakshmi.avinesh | 13 Feb, 2024, 07:03: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by sakshikatewa0 | 08 Feb, 2024, 12:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by saanviyadla | 24 Jan, 2024, 07:06: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×