Prove

Asked by  | 31st Aug, 2008, 06:44: PM

Expert Answer:

we know that (1+w+w2) = 0 and w3 =1

x2 + y2 +z2 = a2+b2+2ab+a2w2+b2w4+2abw3+a2w4+b2w2+2abw3

now putting w3=1 and w4= w

 x2 + y2 +z2 = a2 (1+w+w2)+b2 (1+w+w2)+6ab= 6ab

Answered by  | 6th Sep, 2008, 06:32: PM

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