Prove
Asked by
| 31st Aug, 2008,
06:44: PM
Expert Answer:
we know that (1+w+w2) = 0 and w3 =1
x2 + y2 +z2 = a2+b2+2ab+a2w2+b2w4+2abw3+a2w4+b2w2+2abw3
now putting w3=1 and w4= w
x2 + y2 +z2 = a2 (1+w+w2)+b2 (1+w+w2)+6ab= 6ab
Answered by
| 6th Sep, 2008,
06:32: PM
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