Prove that:

Asked by naina_kli | 6th Jul, 2015, 02:48: PM

Expert Answer:

C o n s i d e r space t h e space L H S colon L H S equals fraction numerator c o t open parentheses 90 minus theta close parentheses over denominator tan theta end fraction plus fraction numerator cos e c open parentheses 90 minus theta close parentheses sin theta over denominator tan open parentheses 90 minus theta close parentheses end fraction equals fraction numerator tan theta over denominator tan theta end fraction plus fraction numerator s e c theta cross times s i n theta over denominator c o t theta end fraction equals fraction numerator t a n theta over denominator t a n theta end fraction plus tan theta cross times s e c theta cross times s i n theta equals 1 plus fraction numerator sin theta over denominator cos theta end fraction cross times s e c theta cross times s i n theta equals 1 plus fraction numerator s i n theta over denominator c o s theta end fraction cross times fraction numerator 1 over denominator c o s theta end fraction cross times s i n theta equals 1 plus fraction numerator s i n theta over denominator c o s theta end fraction cross times fraction numerator s i n theta over denominator c o s theta end fraction equals 1 plus tan theta cross times t a n theta equals 1 plus t a n squared theta equals s e c squared theta

Answered by Vimala Ramamurthy | 7th Jul, 2015, 09:32: AM