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CBSE Class 10 Answered

how to prive
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Asked by farkadeamol9 | 28 Aug, 2020, 10:53: AM
answered-by-expert Expert Answer
Consider,
(1-sin2A)cosec2B+cot2B(1-cos2A)
= (cos2A)(1/sin2B) + (cos2B/sin2B)(sin2A)
= (cos2A/sin2B) + (cos2B sin2A)/sin2B
= (cos2A + cos2B sin2A)/sin2B
Answered by Renu Varma | 31 Aug, 2020, 12:30: PM

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please help me to solve this problem
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how to prive
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Asked by farkadeamol9 | 28 Aug, 2020, 10:53: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
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