CBSE Class 10 Answered
Sin^2A/2+Sin^2(B+C/2)
Asked by adinaditi29 | 14 Mar, 2022, 12:02: PM
The question must be:
In triangle ABC, show that sin2A/2 = sin2(B+C)/2 = 1
Solution:
In a triangle sum of all angles is 180 degrees.
A + B + C = 180o
B + C = 180 - A
B + C/2 = 90 - A/2
sin2 (B + C/2) = sin2 (90 - A/2)
sin2 (B + C/2) = cos2 A/2
Hence, LHS = sin2 A/2 + sin2 (B + C/2) = sin2 A/2 + cos2 A/2 = 1
Answered by Renu Varma | 16 Mar, 2022, 10:38: AM
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