please help me to solve this problem

Asked by kalladaprem | 24th Sep, 2020, 08:20: AM

Expert Answer:

begin mathsize 16px style cosθ space plus sinθ space equals space square root of 2 cosθ
Squaring space on space both space the space sides comma space we space get
open parentheses cosθ space plus sinθ close parentheses squared space equals space open parentheses square root of 2 cosθ close parentheses squared
rightwards double arrow cos squared straight theta space plus space sin squared straight theta space plus space 2 sinθcosθ space equals space 2 cos squared straight theta
rightwards double arrow cos squared straight theta space space minus space space 2 sinθcosθ space space space equals space sin squared straight theta
rightwards double arrow space cos squared straight theta space space minus space space 2 sinθcosθ space plus space sin squared straight theta space equals space 2 sin squared straight theta space space..... space left parenthesis Adding space sin squared straight theta space on space both space the space sides right parenthesis
rightwards double arrow open parentheses cosθ space minus space sinθ close parentheses squared equals 2 sin squared straight theta space space space space.... left parenthesis straight a space minus straight b right parenthesis squared equals space straight a to the power of 2 end exponent minus 2 ab plus straight b squared
Taking space square space root space on space both space the space sides comma space we space get
rightwards double arrow cosθ space minus space sinθ space equals square root of 2 space sinθ space..... hence space proved.

end style

Answered by Yasmeen Khan | 24th Sep, 2020, 01:38: PM