CBSE Class 10 Answered
plzz ans ......
Asked by kirtichawla94 | 11 Mar, 2010, 05:33: PM
Expert Answer
Using sections formula we can obtain the coordinates of point P,
as (-1+9k/(k+1), (3+8k)/(k+1)) = (Xp, Yp)
But since point P lies on the line X-Y+2 = 0 .
Xp - Yp + 2 = 0
[(-1+9k) - (3+8k)]/(k+1) = -2
-4 + k = -2k - 2
k = 2/3
Regards,
Team,
TopperLearning.
Answered by | 11 Mar, 2010, 09:46: PM
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