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Plz elaborate and explain 3rd question
question image
Asked by Harshhacker2580 | 23 Oct, 2020, 08:40: PM
answered-by-expert Expert Answer
 
 
 Step-1 :-
 
Open the load resistance , short the voltage source, Find the equivalent resistance Req of network of resistances .
 
Req = 6.07 Ω
 
Step-2
 
With the determined equivalent resistnce , current drawn from 120 V battery is  120 /6.07 = 19.77 A .
 
Current passing through 7Ω resistor can be calculated as 7.91 A , hence potential difference across load terminals A and B = 7 × 7.91 = 55.35 V
 
Hence Thevenin eq.circuit contains 55.35 V voltage source and 6.07Ω series resitance as shown in figure
 
Answered by Thiyagarajan K | 26 Oct, 2020, 08:19: AM

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