pls solve

Asked by walavalkarsandeep44 | 22nd Jun, 2022, 07:54: PM

Expert Answer:

Change in momenum Δp for one H2 molecule after collision,  Δp = ( 2 m v cos45)
 
Force exerted on wall = rate of change of momentum = Δp / Δt = ( 2 m v cos45)
 
( Δt = 1 sec )
 
Force exerted on wall due to n molecules after collision = ( 2 n m v cos45)
 
Pressure = Force / Area = ( 2 n m v cos45) / A  ......................... (1)
 
Number of H2 molecule hitting the wall = n = 1023
 
mass of H2 molecule = m = 3.22 × 10-27 kg
 
speed of each molecule = v = 103 m/s
 
Area = A = 2 cm2 = 2 × 10-4 m2
 
Pressure is determined from eqn.(1) as
 
P = ( 2 × 1023 × 3.22 × 10-27 × 103 × cos45 ) / ( 2 × 10-4 ) Pa
 
P = 4554 Pa



Answered by Thiyagarajan K | 22nd Jun, 2022, 09:46: PM

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