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CBSE Class 11-science Answered

Pls solve
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Asked by pb_ckt | 11 Jun, 2019, 03:33: PM
answered-by-expert Expert Answer
let space straight theta equals straight a plus straight b given space that space space straight phi space equals straight a minus straight b also tan space straight a space equals space straight k space tan space straight b fraction numerator tan space straight a over denominator tan space straight b end fraction space equals space straight k by space componendo space and space dividendo fraction numerator tan space straight a space minus space tan space straight b over denominator tan space straight a space plus space tan space straight b end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction fraction numerator begin display style fraction numerator sin space straight a over denominator cos space straight a end fraction end style minus begin display style fraction numerator sin space straight b over denominator cos space straight b end fraction end style over denominator fraction numerator sin space straight a over denominator cos space straight a end fraction plus fraction numerator sin space straight b over denominator cos space straight b end fraction end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction fraction numerator begin display style sin space straight a space cos space straight b minus sin space straight b space cos space straight a end style over denominator sin space straight a space cos space straight b plus sin space straight b space cos space straight a end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction fraction numerator begin display style sin space open parentheses straight a minus straight b close parentheses end style over denominator sin space left parenthesis straight a plus straight b right parenthesis end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction fraction numerator begin display style sin space straight phi end style over denominator sin space straight theta end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction
Answered by Arun | 13 Jun, 2019, 10:15: AM

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