CBSE Class 11-science Answered
Pls solve
![question image](https://images.topperlearning.com/topper/new-ate/topr_468275351347488455A.jpeg)
Asked by pb_ckt | 11 Jun, 2019, 15:33: PM
![let space straight theta equals straight a plus straight b
given space that space space straight phi space equals straight a minus straight b
also
tan space straight a space equals space straight k space tan space straight b
fraction numerator tan space straight a over denominator tan space straight b end fraction space equals space straight k
by space componendo space and space dividendo
fraction numerator tan space straight a space minus space tan space straight b over denominator tan space straight a space plus space tan space straight b end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction
fraction numerator begin display style fraction numerator sin space straight a over denominator cos space straight a end fraction end style minus begin display style fraction numerator sin space straight b over denominator cos space straight b end fraction end style over denominator fraction numerator sin space straight a over denominator cos space straight a end fraction plus fraction numerator sin space straight b over denominator cos space straight b end fraction end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction
fraction numerator begin display style sin space straight a space cos space straight b minus sin space straight b space cos space straight a end style over denominator sin space straight a space cos space straight b plus sin space straight b space cos space straight a end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction
fraction numerator begin display style sin space open parentheses straight a minus straight b close parentheses end style over denominator sin space left parenthesis straight a plus straight b right parenthesis end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction
fraction numerator begin display style sin space straight phi end style over denominator sin space straight theta end fraction equals fraction numerator straight k minus 1 over denominator straight k plus 1 end fraction](https://images.topperlearning.com/topper/tinymce/cache/9dcab440679a265de84997436b3dc5e7.png)
Answered by Arun | 13 Jun, 2019, 10:15: AM
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