Pls solve it.

Asked by pb_ckt | 1st May, 2019, 12:07: PM

Expert Answer:

Option (C) is correct.
 
Given:
 
Mass of NaCl = 5.85 g
 
Volume of solution = 1 litre
 
Number of moles =
 
 equals fraction numerator Weight over denominator Molecular space weight end fraction

equals fraction numerator 5.58 over denominator 58.5 end fraction

equals space 0.095 space mole
No. of ions in 1 ml of solution
 
1 mole of NaCl contains 6.23×1023 molecules
 
NaCl ionises into twi ions Na+ Cl
 
1 mole of NaCl =  6.022×1023 × 2
 
                       = 12.044 ×1020 
 
Now 0.095 moles of NaCl will contain,
 
space space 0.095 cross times 12.044 cross times 10 to the power of 20

equals space 1.14 space cross times 10 to the power of 20 space ions

Answered by Varsha | 1st May, 2019, 01:28: PM