ICSE Class 10 Answered
please tell the final answer
![question image](http://images.topperlearning.com/topper/new-ate/top_mob169623029468905866101af96b6-f7bd-4a39-9298-a82b7c3ba2db.jpg)
Asked by shethdhanesh | 02 Oct, 2023, 12:34: PM
Distance traveled from well to first tree then back to well for watering first tree = 10+10 m = 20 m
distance between trees = 5 m
Distance traveled from well to second tree then back to well for watering second tree = 15+15 m = 30 m
Distance traveled from well to third tree then back to well for watering third tree = 20+ 20 m = 40 m
Hence , total distance D travelled to water 25 trees is given by sum of following series
D = 20 m + 30 m + 40 m + ...............................................
Above series is in arithmetic progression that has 25 terms . First term a = 20 and the common difference d = 10 .
Sum of 25 terms is calculated using the formula "
" , where n = 25 is number of terms
![begin mathsize 14px style S subscript n space equals space n over 2 space open square brackets 2 a space plus space left parenthesis n minus 1 right parenthesis d close square brackets end style](https://images.topperlearning.com/topper/tinymce/cache/8c7789138a7bbd9e7d7a5c9b8df673b3.png)
![begin mathsize 14px style D space equals space 25 over 2 open square brackets 2 space cross times space 20 space plus space left parenthesis 25 minus 1 right parenthesis space cross times 10 close square brackets space equals space 3500 space m end style](https://images.topperlearning.com/topper/tinymce/cache/138443dc917128305eacf41fad1894c2.png)
Answered by Thiyagarajan K | 03 Oct, 2023, 09:46: AM
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