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CBSE Class 10 Answered

Please solve following

Asked by jadhavshivam27 | 12 May, 2020, 01:00: PM
Expert Answer
A with rightwards arrow on top times B with rightwards arrow on top equals open vertical bar A with rightwards arrow on top close vertical bar open vertical bar B with rightwards arrow on top close vertical bar C o s theta
C o m p o n e n t space o f space A space a l o n g space B space i s space
open vertical bar A with rightwards arrow on top close vertical bar C o s theta equals fraction numerator A with rightwards arrow on top times B with rightwards arrow on top over denominator open vertical bar B with rightwards arrow on top close vertical bar end fraction
open vertical bar A with rightwards arrow on top close vertical bar C o s theta equals fraction numerator open parentheses 2 i plus 3 j close parentheses times open parentheses i plus j close parentheses over denominator square root of 1 squared plus 1 squared end root end fraction
open vertical bar A with rightwards arrow on top close vertical bar C o s theta equals fraction numerator 5 over denominator square root of 2 end fraction
Answered by Utkarsh Lokhande | 12 May, 2020, 02:11: PM
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