CBSE Class 10 Answered
Please find the attached question,
Asked by ajayrath7 | 06 Apr, 2019, 10:01: AM
Expert Answer
a).
Since both the resistor are connected in series so
Net resistance of the circuit R = 20+4= 24Ω
b).
Using ohms law
I =V/R = 6/24 = 1/4 = 0.25 A
c).
Voltage across electric lamp V = I×R = 0.25×20 = 5 V
Voltage across conductor V = I×R = 0.25×4 = 1 V
Answered by Ankit K | 06 Apr, 2019, 10:13: PM
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