Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 10 Answered

photo attached 

Asked by amaarisa | 13 Jul, 2021, 09:36: AM
Expert Answer
(i) Total current 0.4 A in the circuit flows through 2 Ω resistor and resistor of unknown resistance x Ω
 
(ii) Three resistors 12 Ω , 6 Ω and 3 Ω are in parallel . Hence circuit current 0.4 A is getting divided in these three resitors.
      Hence currents passing through 12 Ω , 6 Ω and 3 Ω are less than 0.4 A
 
Equivalent resistance Req of parallel combination of 12 Ω , 6 Ω and 3 Ω resistors is calculated as follows
 
Req = ( 12 × 6 × 3 ) / [ ( 12 × 6 ) + ( 6 × 3 ) + ( 3 × 12 ) ]  =  (12/7) Ω
 
Current in the circuit = Voltage / Resistance = 6 / [ 2 + (12/7) + x ] = 0.4 = 2/5
 
From above expression we get , x = 79/7 Ω  ≈ 11.7 Ω
Answered by Thiyagarajan K | 13 Jul, 2021, 12:30: PM
CBSE 10 - Physics
Asked by sr558079 | 27 May, 2022, 01:40: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by alka08156 | 17 Jul, 2021, 07:27: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by amaarisa | 13 Jul, 2021, 09:36: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by rameshsanjaay3 | 08 Jun, 2021, 04:07: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by praveengupta2919.9 | 31 May, 2021, 02:53: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by bobyison | 02 May, 2021, 06:35: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by swatipuspapatel | 08 Apr, 2021, 08:02: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by kv252624 | 07 Mar, 2021, 08:33: PM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×