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NEET Class neet Answered

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Asked by Prashant DIGHE | 28 Feb, 2020, 10:01: PM
answered-by-expert Expert Answer
Given:
 
Freezing point depression constant Kf = 2 K
 
m = 0.5 m
 
ΔTf = Kf × m
 
      = 2× 0.5 
 
ΔTf = 1
 
Tinitial = 272 K
 
n = 0.1 mol
 
V = 1 dm3 
 
straight P space equals nRT over straight V

straight P space equals fraction numerator 0.1 cross times 0.08 cross times 272 over denominator 1 end fraction

straight P space equals space 2.176 space atm
 
 
After realising piston,
 
P1V1 = P2V2 
 
2.176 × 1 = 1 × V2 
 
V2 = 2.176 dm3
Answered by Varsha | 01 Mar, 2020, 06:57: PM
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