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CBSE Class 9 Answered

Please answer this question
Asked by Abhijeetoo7 | 06 Jul, 2008, 02:03: PM
answered-by-expert Expert Answer 
In the case of a regular hexagon the formula can be derived by 
thinking of six equilateral triangles meeting at a point.
Let r = the side of the triangle; then the area of each triangle is 
(1/2)r^2*sin(pi/3) = (1/2)r^2*sqrt(3)/2 = (1/4)r^2*sqrt(3).

For six such triangles the area = (3/2)r^2*sqrt(3)
(3/2)r^2*sqrt(3) = 24 sqrt 3
r = 4cm
perimeter = 4*6 = 24cm
Answered by | 06 Jul, 2008, 02:58: PM

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