CBSE Class 11-science Answered
please answer the question given below
![question image](http://images.topperlearning.com/topper/new-ate/top_mob159690728425825987443e26501-9abe-4027-aa75-6cc0b734cfac.jpg)
Asked by 0 JAGLAN | 08 Aug, 2020, 22:51: PM
from figure block of mass M is kept at rest on the floor. Mass of monkey is m (m<M)
Minimum upward acceleration = ?
Equation of motion for mass of block M,
T - Mg =0 ... (1)
Equation of motion for mass of monkey m,
T - mg =ma
Thus,
T = mg + ma ... (2)
Substituting value for T from eq (1) in (2), we get,
Mg = mg + ma
Thus,
![m a space equals space M g space minus space m g space
T h u s comma space
a space equals space fraction numerator open parentheses M space minus space m close parentheses g over denominator m end fraction space equals open parentheses space M over m space minus space 1 close parentheses g space
T h u s comma space m i n i m u m space u p w a r d space a c c e l e r a t i o n space o f space m o n k e y space s o space t h a t space t h e space b l o c k space o f space M space i s space l i f t e d space u p space m u s t space b e space g r e a t e r space t h a n open parentheses space M over m space minus space 1 close parentheses g space](https://images.topperlearning.com/topper/tinymce/cache/f4e4255ff53844b61cfdfc450f47b088.png)
Correct option is (b)
Answered by Shiwani Sawant | 18 Aug, 2020, 00:07: AM
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