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CBSE Class 11-science Answered

please answer the question given below
Asked by 0 JAGLAN | 08 Aug, 2020, 10:51: PM
Expert Answer
from figure block of mass M is kept at rest on the floor. Mass of monkey is m (m<M)
Minimum upward acceleration = ? 
Equation of motion for mass of block M, 
T - Mg =0 ... (1)
 
Equation of motion for mass of monkey m, 
T - mg =ma 
Thus, 
T = mg + ma ... (2) 
 
Substituting value for T from eq (1) in (2), we get, 
Mg  = mg + ma 
 
Thus, 
m a space equals space M g space minus space m g space
T h u s comma space
a space equals space fraction numerator open parentheses M space minus space m close parentheses g over denominator m end fraction space equals open parentheses space M over m space minus space 1 close parentheses g space
T h u s comma space m i n i m u m space u p w a r d space a c c e l e r a t i o n space o f space m o n k e y space s o space t h a t space t h e space b l o c k space o f space M space i s space l i f t e d space u p space m u s t space b e space g r e a t e r space t h a n open parentheses space M over m space minus space 1 close parentheses g space 
Correct option is (b) 
 
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