Asked by | 15th Jan, 2009, 12:22: PM
We know that the diagonals of a parallelogram bisect each other.
In this case, suppose M is the point of intersection of the diagonals AC and BD, then M is the mid point AC as well as BD.
So using the mid point formula, we get, M has coordinates (q+8/2,p+3/2) as the mid point of BD
M has coordinates(9+6/2,4+1/2) as the mid point of AC.
So equating both coordinates, we get,
Answered by | 15th Jan, 2009, 03:26: PM
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