Question # 15
Prove that no value of x exists for which the points A(x,4) , B(1,-2) and C(-3,2) form an isosceles triangle at the vertex B.
Asked by miniprasad | 20th Oct, 2018, 05:14: PM
According to the question,
ABC is an isoscels triangle vertex is at B.
BA = BC
(x - 1)2 + [4 - (-2)]2 = [1 - (-3)]2 + (-2 - 2)2
Solving this we get
x2 - 2x + 5 = 0
If we find discriminant b2 - 4ac it is negative.
Hence, there is no value for x for which given points will form an isoscels triangle.
Answered by Sneha shidid | 22nd Oct, 2018, 12:52: PM
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