one of the satellites of jupiter , has an orbital period of 1.769 days and the radius of the orbit
Asked by | 12th Sep, 2009, 02:15: AM
The time period is, T = 2πR/V,
T2 = 4π2R2/V2 ............(1)
The centripetal force for the satellite's motion is the gravitational force between satellite and Jupiter,
mV2/R = GMm/R2, where m is the mass of the satellite and M is the mass of Jupiter and other symbols have their usual meaning.
V2 = GM/R
Using this V2 in (1),
T2 = 4π2R3/(GM)
M = 4π2R3/(GT2)
M = (4)(3.14)2(4.22x108)3/((6.67x10-11)(1.769x24x3600)2)
= 1.90 x 1027 kg
= 2x1027 kg
Sun's Mass is, 2x1030 kg.
Hence the Jupiter's mass is 1000th that of sun.
Answered by | 4th Nov, 2009, 02:23: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number