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CBSE Class 12-science Answered

Need help with this Chemical Kinetics problem. How do I work out the decomposition rate of [N2O5]? 
question image
Asked by astutijoshi | 03 Jul, 2019, 06:24: PM
answered-by-expert Expert Answer
In this given reaction-
 
2 straight N subscript 2 straight O subscript 5 rightwards arrow 4 NO subscript 2 space plus space straight O subscript 2
space 7.2
7.2 minus 2 straight x space space space space space 4 straight x space space space space space space space straight x

After space 20 space minutes comma space
4 straight x equals 2.4
straight x equals 0.6

So space Concentration space of space straight N subscript 2 straight O subscript 5 space after space 20 space minutes equals space 7.2 minus 2 straight x
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 7.2 minus 1.2
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 6 space mol space straight L to the power of negative 1 end exponent

Now space rate space of space decomposition space of space straight N subscript 2 straight O subscript 5 equals fraction numerator 7.2 minus 6 over denominator 20 end fraction
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals fraction numerator 1.2 over denominator 20 end fraction
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 0.06 space Mol space straight L to the power of negative 1 end exponent space min to the power of negative 1 end exponentn
Answered by Ravi | 04 Jul, 2019, 11:32: AM
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