Mention the gamates produced from genotype AaBbCcDd?
Asked by hemanttkumarr | 2nd Jul, 2018, 08:44: PM
No.of possible gametes can be found through genotype by counting the no.of heterozygous or dissimilar allele pairs present in the genotype. These are denoted by 'n'.
No of possible genotypes = 2n
No. of allele pairs = 4 (Aa, Bb, Cc, Dd)
No. of gametes produced = 2n = 24 = 16
Therefore, a total of 16 gametes can be produced from the genotype AaBbCcDd.
Answered by Sheetal Kolte | 3rd Jul, 2018, 10:13: AM
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