CBSE Class 9 Answered
ATQ,
angle CAP and CBP become angles in the same segment, so they are equal.
so
angle CAP=angleCBP
but angle CBP=B/2... given
so
angle CAP=B/2
Join C ,P.
So ABCP becomes a cyclic quadrilateral,
angle QPC= angle ABC.. as ext angle of a cyclic quadri. is equal to int opp angle.
angle ACP=angle ABP.. angles in the same seg are equal.
but angle ABP=B/2
so
angle ACP=B/2
angle ACQ=180-angle ACB=180-angle ABC=180-B... since AB=AC given,
i.e.
angle ACP+angle PCQ=180-B
[B/2]+angle PCQ=180-B
so
PCQ=180-[3B/2]
Now in triangle PCQ,
angle QPC+angle PCQ+angle Q=180
so substituting the values, we get,
180-[3B/2]+B+angle Q=180
So,
angle Q=B/2,
thus in triangle ACQ,
Angle CAQ=B/2
angle Q=B/2
so the triangle is isoceles
and so
AC=CQ
hence proved