Asked by lakshitas | 27th Feb, 2010, 05:31: PM
angle CAP and CBP become angles in the same segment, so they are equal.
but angle CBP=B/2... given
Join C ,P.
So ABCP becomes a cyclic quadrilateral,
angle QPC= angle ABC.. as ext angle of a cyclic quadri. is equal to int opp angle.
angle ACP=angle ABP.. angles in the same seg are equal.
but angle ABP=B/2
angle ACQ=180-angle ACB=180-angle ABC=180-B... since AB=AC given,
angle ACP+angle PCQ=180-B
Now in triangle PCQ,
angle QPC+angle PCQ+angle Q=180
so substituting the values, we get,
thus in triangle ACQ,
so the triangle is isoceles
Answered by | 28th Feb, 2010, 06:02: PM
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