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magnetic field on centre of triangle Expert Answer Let us find magnetic field induction due to linear current segment of length L and carrying current i .

Let us find magnetic field induction at a point P which is at a distance d from mid point of segment

as shown in figure .

Let idl be a small current segment of length dl at a distance l from mid point .

Magnetic field induction dB at P due to this small segment idl is given by Biot-Savart's law where θ  is angle between small current segment idl and line joining current segment to point P.

If we write sinθ in terms of d and l , then we get  Magnetic field induction B due to full length is given as if we use the substitution , then above integration becomes  .............................(1)

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Now Let us find the magnetic field induction at the centroid of equilateral triangle of side length L Let i be the current passing through the sides in counterclockwise direction.

if we apply eqn.(1) , then we get magnetic field at centroid as ................................. (2)
The factor 3 in above expression is due to superimposition of magnetic field induction
at centroid due to three sides .

Distance d from centroid to sides is given as

d = (1/3) ( √3/2) L  = L / ( 2 √3 )

If we substitute d as above in eqn.(2), then we get Answered by Thiyagarajan K | 21 Dec, 2022, 12:31: AM
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Magnetic field linked through a coil of 50Ω resistance varies with time as shown in graph. Draw (emf v/s t) graph Asked by jhajuhi19 | 21 Aug, 2021, 01:26: AM ANSWERED BY EXPERT
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magnetic field linked through a coil of 50Ω resistance varying with time as shown in graph. Draw the graph of current v/s time. (Given time in sec and flux in wb) Asked by jhajuhi19 | 20 Aug, 2021, 12:32: PM ANSWERED BY EXPERT