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magnetic effect of current
![question image](http://images.topperlearning.com/topper/new-ate/top_mob168969906921954495168320ca0-e2c7-44da-8eac-84af776896e8.jpg)
Asked by mc8may | 18 Jul, 2023, 22:21: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/de6f7471f9377079cb677a284547716a64b77f218bc949.11922221g2.png)
The view of x-z plane of the given configuration of current carrying wire is shown above.
Let us consider a small element of length dz at distance z from mid point of wire-A2 .
Magnetic field B due to current rhrough wire-A1 at the location of dl is
![begin mathsize 14px style B space equals space fraction numerator mu subscript o I over denominator 2 straight pi end fraction fraction numerator 1 over denominator square root of z squared plus 3 end root end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/b9abdd7759364f362959be7524d5fbfe.png)
Magnitude of
is calculated as follows
![begin mathsize 14px style integral B times d z end style](https://images.topperlearning.com/topper/tinymce/cache/36480cd55dd458454d4b66f7d4696009.png)
![begin mathsize 14px style integral B times d z space equals space fraction numerator mu subscript o I over denominator 2 straight pi end fraction integral subscript negative square root of 3 end subscript superscript plus square root of 3 end superscript fraction numerator d z over denominator square root of z squared plus 3 end root end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/30ed75ce5dd9d86abc807e369252e1a5.png)
![begin mathsize 14px style fraction numerator mu subscript o I over denominator 2 pi end fraction space ln left parenthesis space 3 space plus space 2 square root of 2 space right parenthesis end style](https://images.topperlearning.com/topper/tinymce/cache/c4913cf33a5b61def6b4776a42629372.png)
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