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Find magnetic field Bp/Bc=?
Asked by Vipulgautam050 | 27 Oct, 2021, 11:47: PM
Let us consider a small current element of length dl at angular position θ as shown in figure.

magnetic field dB at P is given as

...............................(1)
let us condier dl as arc length ( R dθ ), where dθ is angle subtended by dl at centre C

vector = ( -R cosθ ) - ( R + R sinθ )
unit vector = (1/r ) [ ( -R cosθ ) - ( R + R sinθ ) ]
where r is magnitude of vector
We get magnetic field dB from eqn.(1) as

.........................(2)

From above expression of  ( dl × )  , we see that if we integrate ( dl × ) from θ = 0 to θ = π
to get magnetic field due to full semicircular arc , we get zero

hence BP = 0

Magnetic field BC at centre is determined as

Answered by Thiyagarajan K | 28 Oct, 2021, 11:47: AM
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