kindly assist

Asked by Kanhaiya | 16th Sep, 2015, 07:57: PM

Expert Answer:

(a) Between A and Bbus has maximum speed i.e. 20 m/s. Hence, Between A nd B of the journey the bus was moving fastest.
(b) During C and the bus was at rest.
(c) The acceleration between the points D and E is nothing but, acceleration of the body in time interval 10 s to 44 s
    begin mathsize 12px style equals space fraction numerator 0 minus 12 over denominator 44 minus 40 end fraction space equals space fraction numerator negative 12 over denominator 4 end fraction space equals space 3 space straight m divided by straight s squared end style
(d) The graph BC represents the retardation.
(e) The distance travelled will be equal to the area under the graph from 0 to 28 seconds.
     Area of the trapezium OABC = begin mathsize 12px style fraction numerator AB space plus space OC over denominator 0 end fraction space cross times space straight A space to space point space at space 8 space straight s space equals space fraction numerator 12 space plus space 28 over denominator 2 end fraction space cross times space 20 space equals space 160 space straight m space end style

Answered by Priyanka Kumbhar | 18th Sep, 2015, 11:07: AM