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in YDSE how many maxima can be obtained on the screen if wavelength of light used is 200nm and d=700nm ??
Asked by sarveshvibrantacademy | 22 May, 2019, 10:10: AM
answered-by-expert Expert Answer
For constructive interference
 theta equals 2 pi n theta equals k triangle x 2 πn equals fraction numerator 2 straight pi over denominator straight lambda end fraction triangle straight x triangle straight x equals nλ Also space path space difference space triangle straight x equals dSinθ Therefore dSinθ equals nλ straight n subscript max equals dSinθ over straight lambda Sinθ less or equal than 1 straight n subscript max equals straight d over straight lambda straight n subscript max equals fraction numerator 700 nm over denominator 200 nm end fraction straight n subscript max equals 7 over 2 Maximum space possible space value space of space straight n equals 3 Therefor space the space number space of space maxima space formed 2 straight n plus 1 2 cross times 3 plus 1 equals 7 left parenthesis 3 space above space 3 space below space and space 1 space at space center right parenthesis
Answered by Utkarsh Lokhande | 22 May, 2019, 17:10: PM
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