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In this quesn, how they have assumed thta final pressure of both the vessels will be same.
Asked by aaryamanmodern | 17 Jan, 2023, 10:18: PM
Initially both vessels of equal volume V is at same pressure Po and absolute temperature  To .

Let n be number of moles in each vessel . Hence we write ideal gas equation as

where R is universal gas constant. Hence we write

..............................................(1)
If one vessel is maintained at temperature To and other one is maintained at temperature T1  ( T1 > To ) ,

then vessel at temperature To will have more number of moles and vessel at temperature T1

will have less number of moles because both vessels are connected by a narrow tube

and they are at equal pressure.

Let n1 be the number of moles in the vessel that is maintained at temperature To .

Let n2 be the number of moles in the vessel that is maintained at temperature T1 .

Then we have ,     .............................(2)
and   ......................................(3)

By adding eqn.(2) and (3) , we get

.............................(4)
Since number of moles in both vessels remain constant, n1 + n2 = ( 2 n )

Hence we equate eqn.(1) and (4) to get

Let us substitute values , Po = 105 kPa ,  To = 300 K  and  T1 = 400 K

P = 105 × ( 800/700) = 120 kPa
Answered by Thiyagarajan K | 17 Jan, 2023, 11:40: PM

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